在线英语听力室

新东方背诵文选 L50. Cells and Temperature

时间:2005-05-03 16:00:00

搜索关注在线英语听力室公众号:tingroom,领取免费英语资料大礼包。

(单词翻译)


Cells cannot remain alive outside certain limits of temperature and much narrower limits mark the boundaries of effective functioning. Enzyme1 systems of mammals and birds are most efficient only within a narrow range around 37C;a departure of a few degrees from this value seriously impairs2 their functioning. Even though cells can survive wider fluctuations3 the integrated actions of bodily systems are impaired4. Other animals have a wider tolerance5 for changes of bodily temperature.
For centuries it has been recognized that mammals and birds differ from other animals in the way they regulate body temperature. Ways of characterizing the difference have become more accurate and meaningful over time, but popular terminology6 still reflects the old division into "warm-blooded" and "cold-blooded" species; warm-blooded included mammals and birds whereas all other creatures were considered cold- blooded. As more species were studied, it became evident that this classification was inadequate7. A fence lizard8 or a desert iguana-each cold-blooded----usually has a body temperature only a degree or two below that of humans and so is not cold. Therefore the next distinction was made between animals that maintain a constant body temperature, called home0therms, and those whose body temperature varies with their environments, called poikilotherms. But this classification also proved inadequate, because among mammals there are many that vary their body temperatures during hibernation9. Furthermore, many invertebrates10 that live in the dep`hs of `@e o#eaf never `Pperien`  chang! in the  epths n the oa@an leve exper`nce ch`@ge In t@e #hil, of the Deep wapdr, and  he)p bh@y tempa atures emahn bnstant&
分享到:

Error Warning!

出错了

Error page: /?aid=1739&mid=3
Error infos: Got error 28 from storage engine
Error sql: select `l`.`tag`,`l`.`index`,`l`.`level_id`,`b`.`id`,`b`.`word`,`b`.`spell`,`b`.`explain`,`b`.`sentence`,`b`.`src` from `new_wordtaglist` `l` left join `new_word_base` `b` on `l`.`tag`=`b`.`word` where `l`.`arc_id`='1739' and `l`.`level_id`>='' group by `b`.`word` order by `l`.`index` asc

本文本内容来源于互联网抓取和网友提交,仅供参考,部分栏目没有内容,如果您有更合适的内容,欢迎 点击提交 分享给大家。